GCSE Tutoring Programme
"Our chosen students improved 1.19 of a grade on average - 0.45 more than those who didn't have the tutoring."
In order to access this I need to be confident with:
Simplifying expressions Factors and multiples Powers and roots Algebraic expressions Adding and subtracting negative numbers Multiplying and dividing negative numbersThis topic is relevant for:
Here we break down everything you need to know about expanding brackets. You’ll learn how to expand single brackets and double brackets in order to leave a simplified algebraic expression.
At the end you’ll find expanding brackets worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.
To expanding brackets means multiplying each term in the brackets by the expression outside the brackets.
Expanding brackets is the reverse process of factorisation and is sometimes referred to as multiplying out. In effect by expanding brackets you are removing the brackets.
To expand brackets we multiply everything outside of the bracket, by everything inside the bracket. For example if we expand
We will get
This lesson is part of our series of lessons to support revision on algebraic expressions. Related step by step guides include:
Download a free expanding brackets worksheet with 20+ reasoning and applied questions, answers and mark scheme to help your students prepare for GCSEs. Includes reasoning and applied questions.
DOWNLOAD FREEDownload a free expanding brackets worksheet with 20+ reasoning and applied questions, answers and mark scheme to help your students prepare for GCSEs. Includes reasoning and applied questions.
DOWNLOAD FREE‘Multiplying out brackets’ or ’multiply out’ is another term for expanding brackets. It means exactly the same thing. “Expand the brackets” is the same as “multiply out the brackets”, it just gives the additional clue that when we expand brackets, we are multiplying everything outside the brackets by everything inside the brackets.
One use of brackets in maths in maths is to group items together, another is to give information about the order of operations.
E.g
Here is a rectangle.
Its perimeter is:
(x+8)+(x-3)+(x+8)+(x-3)Here the brackets are used to group the terms so that the expressions for the sides are clear.
The perimeter can also be written as:
2(x+8)+2(x-3)Here brackets are needed to preserve that the whole expressions for the sides are doubled to find the perimeter of a rectangle.
In order to expand brackets you need to multiply the terms outside the brackets (or parentheses) by the terms inside the brackets. There are three main ways to do this, each of which is explained below.
3(2x + 1) = 6x + 3
Expressions with two terms like
2. Expanding double brackets
(x + 5)(x – 1) = x2+ 4x – 5
Expressions with three terms like
Terms that are raised to the power of
3. Expanding triple brackets
(x + 1)(x + 2)(x + 3) = x3 + 6x + 11x + 6
A polynomial expression consists of two or more algebraic terms.
There is a fourth, more complex situation in which you may need to use your expanding brackets knowledge but this is usually only seen on the higher level GCSE maths papers so is not part of this lesson.
In summary, in order to expand brackets involving surds we multiply every term outside the brackets by every term inside the brackets and follow the rules of surds.
For example if we expand
We will get
Step-by-step guide: Surds
To expand a single bracket we multiply the term outside of the bracket by everything inside of the bracket.
In order to expand single brackets:
Expand:
2(x + 3)
✕ | x | + 3 |
2 | 2x |
2Multiply the value outside the bracket
✕ | x | + 3 |
2 | 2x | + 6 |
The answer is positive so we need to write +
Expand:
− 3(y − 4)
Multiply the term outside of the bracket (− 3) by the first term inside the bracket (y).
✕ | y | − 4 |
− 3 | − 3y |
− ✕ + = − so the answer is negative.
Multiply the term outside the bracket (− 3)by the second term inside the bracket (− 4).
✕ | y | − 4 |
− 3 | − 3y | + 12 |
− ✕ − = + so the answer is positive. We need to write
Expand:
3x(4x − 2y)
Multiply the term outside of the bracket (3x) by the first term inside the bracket (4x).
✕ | 4x | − 2y |
3x | 12x2 |
Multiply the term outside the bracket (3x) by the second term inside the bracket (−2y).
✕ | 4x | − 2y |
3x | 12x2 | − 6xy |
− ✕ + = − so the answer is negative. We need to write
Expand:
2x(3 − 5y + 6x2)
Multiply the value outside of the bracket (2x) by the first term inside the bracket (3).
✕ | 3 | − 5y | 6x2 |
2x | 6x |
Multiply the value outside the bracket (2x) by the second term inside the bracket (−5y).
✕ | 3 | − 5y | 6x2 |
2x | 6x | − 10xy |
− ✕ + = − so the answer is negative. We need to write −
Multiply the value outside the bracket (2x) by the third term inside the bracket (6x^{2}).
✕ | 3 | − 5y | 6x2 |
2x | 6x | − 10xy | + 12x3 |
The answer is positive so we need to write +
1. Expand: 6(y-2)
With a single bracket expansion, we must be sure to multiply each term inside the bracket by the number in front of the bracket.
2. Expand: -2(x+6)
With a single bracket expansion, we must be sure to multiply each term inside the bracket by the number in front of the bracket. Care must be taken when multiplication involves negative numbers.
3. Expand: y(2y-3)
With a single bracket expansion, we must be sure to multiply each term inside the bracket by the number in front of the bracket. Make sure to include the correct index numbers.
4. Expand: -5x(2x+4)
With a single bracket expansion, we must be sure to multiply each term inside the bracket by the number in front of the bracket. Make sure to include the correct index numbers. Care must be taken when multiplication involves negative numbers.
5. Expand: 4(8-3x+2y)
With a single bracket expansion, we must be sure to multiply each term inside the bracket by the number in front of the bracket.
6. Expand: 3y(2+7y-4x)
With a single bracket expansion, we must be sure to multiply each term inside the bracket by the number in front of the bracket. Make sure to include the correct index numbers.
To expand double brackets we multiply every term in the first bracket, by every term in the second bracket.
In order to expand double brackets follow these steps:
Expand and simplify:
(x+2)(x+3)
✕ | x | + 3 |
x | ||
+ 2 |
2Fill in the grid by multiplying each of the terms together.
✕ | x | + 3 |
x | x2 | + 3x |
+ 2 | + 2x | + 6 |
x ✕ x = x2 x ✕ 3 = 3x x ✕ 2 = 2x 2 ✕ 3 = 6
3Write out each of the terms and simplify the expression by collecting like terms.
x2 + 3x + 2x + 6 = x2 + 5x + 6
Expand and simplify:
(x + 5)(x − 1)
Draw a grid and insert the terms of the first and second brackets.
✕ | x | − 1 |
x | ||
+ 5 |
Fill in the grid by multiplying each of the terms together.
✕ | x | − 1 |
x | x2 | − x |
+ 5 | + 5x | − 5 |
x ✕ x = x2 x ✕ − 1 = − x
+ ✕ − = − so the answer is negative.
x ✕ 5 = 5x 5 ✕ − 1 = − 5
+ ✕ − = − so the answer is negative.
Write out each of the terms and simplify the expression by collecting like terms.
x2 − x + 5x − 5 x2 + 4x − 5
Expand and simplify:
(2x − 3)(x + 4)
Draw a grid and insert the terms of the first and second brackets.
✕ | x | + 4 |
2x | ||
− 3 |
Fill in the grid by multiplying each of the terms together.
✕ | x | + 4 |
2x | 2x2 | + 8x |
− 3 | − 3x | − 12 |
2x ✕ x = 2x2 2x ✕ 4 = 8x x ✕ − 3 = − 3x
+ ✕ − = − so the answer is negative.
4 ✕ − 3 = − 12
+ ✕ − = − so the answer is negative.
Write out each of the terms and simplify the expression by collecting like terms.
2x2 + 8x − 3x − 12 2x2 + 5x − 12
Expand and simplify:
(3x − 4)2
Draw a grid and insert the terms of the first and second brackets.
(3x − 4)2 = (3x − 4)(3x − 4)
Remember: when we square something (raise it to the power of 2) we multiply it by itself.
✕ | 3x | − 4 |
3x | ||
− 4 |
Fill in the grid by multiplying each of the terms together.
✕ | 3x | − 4 |
3x | 9x2 | − 12x |
− 4 | − 12x | + 16 |
3x ✕ 3x = 9x2 3x ✕ − 4 = − 12x 3x ✕ − 4 = − 12x
+ ✕ − = − so the answer is negative.
− 4 ✕ − 4 = + 16
− ✕ − = + so the answer is positive.
Write out each of the terms and simplify the expression by collecting like terms.
9x2 − 12x − 12x + 16 9x2 − 24x + 16
1. Expand and simplify: (x+5)(x+6)
(x+5)(x+6)
Expanding the brackets gives
x^{2}+6x+5x+30
and then we can collect like terms
x^{2}+11x+30
2.Expand and simplify: (x-4)(x+2)
Expanding the brackets gives
x^{2}+2x-4x-8
and then we can collect like terms
x^{2}-2x-8
3.Expand and simplify: (2x+3)(x+4)
Expanding the brackets gives
2x^{2}+8x+3x+12
and then we can collect like terms
2x^{2}+11x+12
4. Expand and simplify: (3x-2)(x+1)
Expanding the brackets gives
3x^{2}+3x-2x-2
and then we can collect like terms
3x^{2}+x-2
5. Expand and simplify: (x-4)^{2}
means the same as
(x-4)(x-4)
so we can expand as usual
x^{2}-4x-4x+16
and then collect like terms
x^{2}-8x+16
6.Expand and simplify: (2x+5)^{2}
means the same as
(2x+5)(2x+5)
so we can expand as usual
4x^{2}+10x+10x+25
and then collect like terms
4x^{2}+20x+25
To expand triple brackets we first multiply the first two brackets together. We then multiply every term in this new expression by every term in the third bracket.
In order to expand triple brackets:
Expand and simplify:
(x + 1)(x + 2)(x + 3)
✕ | x | + 2 |
x | x2 | + 2x |
+ 1 | + x | + 2 |
x ✕ x = x2 x ✕ 2 = 2x x ✕ 1 = x 1 ✕ 2 = 2
2Write out each of the terms and simplify the expression by collecting like terms.
x2 + 2x + x + 2 x2 + 3x + 2
3Draw a grid, insert the terms from this new expression and the third bracket, then fill it in by multiplying each of the terms together.
✕ | x2 | + 3x | + 2 |
x | x3 | + 3x2 | + 2x |
+ 3 | + 3x2 | + 9x | + 6 |
x ✕ x2 = x3 x ✕ 3x = 3x2 x ✕ 6 = 6x 3 ✕ x2 = 3x2 3 ✕ 3x = 9x 3 ✕ 6 = 18
4Write out each of the terms and simplify the expression by collecting like terms.
x3 + 3x2 + 3x2 + 9x + 2x + 6 x3 + 6x2 + 11x + 6
Expand and simplify:
(x + 3)2(x − 1)
Draw a grid, insert the terms of the first and second brackets, then fill it in by multiplying each of the terms together.
✕ | x | + 3x |
x | x2 | + 3x |
+ 3 | + 3x | + 9 |
(x + 3)2 = (x + 3)(x + 3) x ✕ x = x2 x ✕ 3 = 3x x ✕ 3 = 3x 3 ✕ 3 = 9
Write out each of the terms and simplify the expression by collecting like terms.
x2 + 3x + 3x + 9 x2 + 6x + 9
Draw a grid, insert the terms from this new expression and the third bracket, then fill it in by multiplying each of the terms together.
✕ | x2 | + 6x | + 9 |
x | x3 | + 6x2 | + 9x |
− 1 | − x2 | − 6x | − 9 |
x ✕ x2 = x3 x ✕ 6x = 6x2 x ✕ 9 = 9x − 1 ✕ x2 = − x2 − 1 ✕ 6x = − 6x − 1 ✕ 9= − 9
Write out each of the terms and simplify the expression by collecting like terms.
x3 + 6x2 − x2 + 9x − 6x − 9 x3 + 5x2 + 3x − 9
1. Expand and simplify: (x+2)(x+3)(x+4)
Expanding the first two brackets gives
(x^{2}+3x+2x+6)(x+4)
or
(x^{2}+5x+6)(x+4)
and then expanding again
x^{3}+4x^{2}+5x^{2}+20x+6x+24
Collect like terms
x^{3}+9x^{2}+26x+24
2. Expand and simplify: (x+3)(x-2)^2
can be written as
(x+3)(x-2)(x-2)
Expanding the two identical brackets first gives
(x+3)(x^{2}-2x-2x+4) (x+3)(x^{2}-4x+4)
and expanding again
x^{3}-4x^{2}+4x+3x^{2}-12x+12
then collect like terms
x^{3}-x^{2}-8x+123.Expand and simplify: (2x+1)^3
(2x+1)^{3}
can be written as
(2x+1)(2x+1)(2x+1)
Expanding two of the brackets gives
(2x+1)(4x^{2}+2x+2x+1)
(2x+1)(4x^{2}+4x+1)
and expanding again
8x^{3}+8x^{2}+2x+4x^{2}+4x+1
then collect like terms
8x^{3}+12x^{2}+6x+1
2(6x2 − 3x) = 12x2 − 3x ✖
Here we have multiplied the value outside of the brackets by the first term inside of the bracket, but not the second term.
The correct answer is
We need to multiply all the terms inside the bracket.
+ ✕ + = +
− ✕ − = +
e.g. 2 ✕ 3 = 6
e.g. − 2 ✕ − 3 = 6
4 ✕ 5 = 20
− 4 ✕ − 5 = 20
+ ✕ − = −
− ✕ + = −
e.g. 2 ✕ − 3 = − 6
e.g. − 2 ✕ 3 = − 6
4 ✕ − 5 = − 20
− 4 ✕ 5 = − 20
− 4(3y − 5) = − 12y − 20 ✖
Here we have not used − ✕ − = +
− 4 ✕ − 5 = + 20
The correct answer is
32 = 3 ✕ 3 x2 = x ✕ x (5y)2 = 5y ✕ 5y
(x + 3)2 = (x + 3)(x + 3) ✔ NOT x2 + 9 ✖
1. Expand: 3(x – 2)
3x – 6
(1 mark)
2. Expand: 4x(2x – 7)
8x2 – 28x
(1 mark)
3. Expand and simplify: 5(x – 3) – 3(x + 5)
2x – 30
(2 marks)
You have now learned how to:
Prepare your KS4 students for maths GCSEs success with Third Space Learning. Weekly online one to one GCSE maths revision lessons delivered by expert maths tutors.
Find out more about our GCSE maths tuition programme.