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Here is everything you need to know about algebraic expressions for GCSE maths (Edexcel, AQA and OCR). You’ll learn what algebraic expressions are, how to simplify algebraic expressions, and the different methods for using algebraic expressions.
Look out for the algebraic expression worksheets, word problems and exam questions at the end.
Overview of this topic: Algebra – Maths GCSE
An algebraic expression is a set of terms with letters and numbers that are combined using addition
An expression that contains two terms is called a binomial.
An expression that contains three terms is called a trinomial.
An algebraic term is either a single number or variable
E.g. ‘3’ or ‘x’ or ‘z’.
A term can also be a number and a variable multiplied together/
E.g. ‘2a’ or ‘6y’ or ‘x2’ or ‘4xy’.
When 2 or more algebraic terms are added (or subtracted) they form an algebraic expression.
Equivalent expressions are expressions which are the same, but look different. For example the expression 3x+4y is equivalent to 4y+3x.
Let’s define some of the keywords when using algebraic notation:
A variable is a symbol (often a letter) that is used to represent an unknown quantity.
Variables can also have exponents (be raised to a certain power).
A coefficient is the value that is before a variable. It tells us how many lots of the variable there is.
Here
A term is a number by itself, a variable by itself, or a combination of numbers and letters. If the term includes a variable it is called an algebraic term.
An expression that contains one term is called a monomial.
A polynomial expression consists of two or more algebraic terms.
Get your free algebraic expressions worksheet of 20+ questions and answers. Includes reasoning and applied questions.
DOWNLOAD FREEGet your free algebraic expressions worksheet of 20+ questions and answers. Includes reasoning and applied questions.
DOWNLOAD FREEThere are various methods of using algebraic expressions and performing algebraic operations. These are summarised below.
For examples, practice questions and worksheets on each one follow the links to the step by step guides below or go straight to factorising and simplifying expressions.
Example of collecting like terms
So
Example of multiplying and dividing algebra
So
Example of expanding brackets
Multiply every term outside the bracket by every term inside the bracket.
✕ | 2x | + 5 |
3 | 6x | + 15 |
Example of algebraic fractions
Divide the numerator and the denominator by
Example of writing and simplifying algebraic expressions
Write an expression for the perimeter of the shape.
Example of factorising in single brackets
Example of factorising quadratic expressions into two brackets
Example of difference of two squares
An algebraic expression is different from an equation and a formula.
An expression is a set of terms that are combined using arithmetic operations:
An equation is an expression that equals something.
We can solve equations to work out the value of the unknown variable
Algebraic formulae are a set of instructions which give a desired result.
E.g.
Circumference of a Circle = πd
Brackets are sometimes referred to as parentheses.
1. Simplify:
6x^{2}y-2x^{2}y+4x^{2}-5x^{2}
By considering like terms in the expression 6x^{2}y-2x^{2}y+4x^{2}-5x^{2} we have 6x^{2}y-2x^{2}y=4x^{2}y and 4x^{2}-5x^{2}=-x^{2} which simplifies to 4x^{2}y-x^{2} .
2. Write an expression for the area of the parallelogram:
For the area, we need to multiply the length (3x+1) of the base and the perpendicular height (2x+1) .
Area =(3x+1)(2x+1)=6x^{2}+5x+13. Simplify:
\frac{9x^{2}y}{15x^{3}}
The numerator and denominator of \frac{9x^{2}y}{15x^{3}} have a highest common factor of 3x^{2} . Therefore, we divide through by 3x^{2} resulting in the simplified algebraic fraction.
4. Simplify:
\frac{x^{2}-3x-10}{x^2-25}
The numerator can be factorised as the product of two brackets
x^{2}-3x-10=(x+2)(x-5)The denominator can be factorised as it is the difference of two squares
x^{2}-25=(x+5)(x-5)This means we can write the fraction as
\frac{(x+2)(x-5)}{(x+5)(x-5)}The numerator and denominator have a common factor of x-5 , which we cancel, leaving the simplified fraction.
5. Simplify:
3x(4-5x+2y)
We need to multiply each term inside the bracket by 3x
3x\times4=12x\\ 3x\times(-5x)=-15x^{2}\\ 3x\times2y=6xywhich we can combine into the expression we need as required.
6. Expand and simplify:
4(2x-1)-3(x+6)
We can expand each bracket one at a time
4(2x-1)=8x-4and
-3(x+6)=-3x-18This can be further simplified by collecting like terms
8x-4-3x-18=5x-227. Fully factorise:
2{x}^2+x-6
Correct answer:
=(2x-3)(x+2)
To factorise the quadratic expression, we are looking for numbers that multiply to -12 and sum to +1. By considering factor pairs, we conclude that we need to use +4 and -3.
We can rewrite
2x^{2}+x-6as 2x^{2}+4x-3x-6
which can be factorised as
2x(x+2)-3(x+2)or more concisely
(2x-3)(x+2)8. Fully factorise:
4{x}^2-25
Correct answer:
(2 x+5)(2 x-5)This is a special case (difference of two squares), which means we can take square roots of the coefficient of x and the constant term, then write one bracket with a + sign and the other bracket with a – sign.
1. Simplify: 4f – 2e + 3f + 5e
7f + 3e
(2 marks)
2. Expand and simplify: 4x(2x – 7)
8x2 – 28x
(2 marks)
3. Simplify:
\[\frac{15x^{3}y^{2}}{5xy^{3}}\]
\[=\frac{3x^{2}}{y}\]
(2 marks)
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