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Ratios Whole numbers Improper fraction to mixed number Numerator and denominatorHere you will learn about multiplying fractions including how to multiply fractions together, multiply fractions by whole numbers, and multiply mixed numbers.
Students will first learn about multiplying unit fractions and whole numbers as part of number and operations in fractions in 4th grade. They will build on this understanding and multiply fractions by fractions as a part of number and operations in fractions in 5th grade.
Multiplying fractions is multiplying one or more numbers that are in fraction form. Fractions can be multiplied using models or the algorithm.
For example…
4 \times \cfrac{1}{3}
Using models:
The model shows \cfrac{1}{3} of 4, so 4 \times \cfrac{1}{3} = \cfrac{4}{3}.
You can also think of 4 \times \cfrac{1}{3} as 4 groups of \cfrac{1}{3} or \cfrac{1}{3}+\cfrac{1}{3}+\cfrac{1}{3}+\cfrac{1}{3}, which is \cfrac{4}{3}.
Using the algorithm:
Write 4 as an improper fraction, 4=\cfrac{4}{1}, then multiply the numerators together, then the denominators:
\cfrac{4}{1} \times \cfrac{1}{3}=\cfrac{4}{3}.
3 \times \cfrac{2}{5}
Using models:
The model shows \cfrac{2}{5} of 3, so 3 \times \cfrac{2}{5}=\cfrac{6}{5}.
You can also think of 3 \times \cfrac{2}{5} as 3 groups of \cfrac{2}{5} or \cfrac{2}{5}+\cfrac{2}{5}+\cfrac{2}{5}, which is \cfrac{6}{5}.
Using the algorithm:
Write 3 as an improper fraction, 3=\cfrac{3}{1}, then multiply the numerators together, then the denominators:
\cfrac{3}{1} \times \cfrac{2}{5}=\cfrac{6}{5}.
\cfrac{1}{2} \times \cfrac{1}{3}
Using models:
In the model, \cfrac{1}{3} is yellow and \cfrac{1}{2} is blue.
The product is where the fractions overlap in green.
The model shows \cfrac{1}{3} of \cfrac{1}{2}, so \cfrac{1}{2} \times \cfrac{1}{3}=\cfrac{1}{6}.
Using the algorithm:
Multiply the numerators together, then the denominators: \cfrac{1}{2} \times \cfrac{1}{3}=\cfrac{1}{6}.
Using models:
In the model, 1 \cfrac{2}{3} is yellow and 2 \cfrac{1}{6} is blue.
The product is where the mixed numbers overlap.
The model shows 1 \cfrac{2}{3} groups of 2 \cfrac{1}{6}.
Notice you have 2 wholes and moving \cfrac{1}{3} to \cfrac{2}{3} is \cfrac{3}{3} which makes another whole.
Then there is also \cfrac{1}{3}, \cfrac{1}{6} and \cfrac{2}{18}.
To find the product, you add these fractions to the 3 wholes.
\begin{aligned} & 3+\cfrac{1}{3}+\cfrac{1}{6}+\cfrac{2}{18} \\\\ & =3+\cfrac{1 \times 6}{3 \times 6}+\cfrac{1 \times 3}{6 \times 3}+\cfrac{2}{18} \\\\ & =3+\cfrac{6}{18}+\cfrac{3}{18}+\cfrac{2}{18} \\\\ & =3 \cfrac{11}{18} \end{aligned}Using the algorithm:
Convert the mixed numbers to improper fractions.
\hspace{1cm} 2 \cfrac{1}{6}=\cfrac{13}{6} \hspace{1cm} and \hspace{1cm} 1 \cfrac{2}{3}=\cfrac{5}{3}
Multiply the numerators together, then the denominators: \cfrac{13}{6} \times \cfrac{5}{3}=\cfrac{65}{18}.
Write \cfrac{65}{18} as a mixed number: 3 \cfrac{11}{18}.
How does this relate to 4th grade math and 5th grade math?
In order to multiply fractions with models:
In order to multiply fractions with the algorithm:
In order to multiply whole numbers or mixed numbers by fractions with the algorithm:
Use this quiz to check your grade 4 to 6 students’ understanding of fraction operations. 10+ questions with answers covering a range of 4th to 6th grade fraction operations topics to identify areas of strength and support!
DOWNLOAD FREEUse this quiz to check your grade 4 to 6 students’ understanding of fraction operations. 10+ questions with answers covering a range of 4th to 6th grade fraction operations topics to identify areas of strength and support!
DOWNLOAD FREESolve \cfrac{2}{5} \times \cfrac{3}{8} with a model.
Draw a rectangle. Divide one side into fifths.
Divide the other side into eighths.
2Connect the fractions all the way across with \bf{2} different colors.
Shade in \cfrac{2}{5} with yellow and \cfrac{3}{8} with blue.
3Count the overlap.
The product is where the fractions overlap in green.
The model shows \cfrac{3}{8} of \cfrac{2}{5}, so \cfrac{2}{5} \times \cfrac{3}{8}=\cfrac{6}{40}, because there are 6 green squares and the whole has 40 squares in total.
4If possible, simplify or convert to a mixed number.
The product can be simplified.
Both 6 and 40 have a factor of 2, so they can be divided by 2 : \cfrac{6 \; \div \; 2}{40 \; \div \; 2}=\cfrac{3}{20}.
So, \cfrac{2}{5} \times \cfrac{3}{8}=\cfrac{6}{40} \, or \, \cfrac{3}{20}.
Solve \cfrac{3}{4} \times \cfrac{1}{6} with a model.
Draw one fraction horizontally and the other vertically.
Draw a rectangle. Divide one side into fourths.
Divide the other side into eighths.
Connect the fractions all the way across with \bf{2} different colors.
Shade in \cfrac{3}{4} with yellow and \cfrac{1}{6} with blue.
Count the overlap.
The product is where the fractions overlap in green.
The model shows \cfrac{1}{6} of \cfrac{3}{4}, so \cfrac{3}{4} \times \cfrac{1}{6}=\cfrac{3}{24}, because there are 3 green squares and the whole has 24 squares in total.
If possible, simplify or convert to a mixed number.
The product can be simplified.
Both 3 and 24 have a factor of 3, so they can be divided by 3 : \cfrac{3 \; \div \; 3}{24 \; \div \; 3}=\cfrac{1}{8}.
So, \cfrac{3}{4} \times \cfrac{1}{6}=\cfrac{3}{24} \, or \, \cfrac{1}{8}.
Solve \cfrac{5}{12} \times \cfrac{2}{3}.
Multiply the numerators together.
\cfrac{5}{12} \times \cfrac{2}{3}=\cfrac{10}{}
Multiply the denominators together.
\cfrac{5}{12} \times \cfrac{2}{3}=\cfrac{10}{36}
If possible, simplify or convert to a mixed number.
The product can be simplified.
Both 10 and 36 have a factor of 2, so they can be divided by 2 : \cfrac{10 \; \div \; 2}{36 \; \div \; 2}=\cfrac{5}{18}.
So, \cfrac{5}{12} \times \cfrac{2}{3}=\cfrac{10}{36} \, or \, \cfrac{5}{18}.
Solve \cfrac{1}{2} \times \cfrac{7}{10}.
Multiply the numerators together.
\cfrac{1}{2} \times \cfrac{7}{10}=\cfrac{7}{}
Multiply the denominators together.
\cfrac{1}{2} \times \cfrac{7}{10}=\cfrac{7}{20}
If possible, simplify or convert to a mixed number.
The product cannot be simplified. 7 and 20 only have a common factor of 1.
So, \cfrac{1}{2} \times \cfrac{7}{10}=\cfrac{7}{20}.
Solve \cfrac{2}{9} \times 4.
Convert to improper fractions.
Write 4 as an improper fraction, 4=\cfrac{4}{1}.
Multiply the numerators together.
\cfrac{2}{9} \times \cfrac{4}{1}=\cfrac{8}{}
Multiply the denominators together.
\cfrac{2}{9} \times \cfrac{4}{1}=\cfrac{8}{9}
If possible, simplify or convert to a mixed number.
The product cannot be simplified. 8 and 9 only have a common factor of 1.
So, \cfrac{2}{9} \times \cfrac{4}{1}=\cfrac{8}{9}.
Solve \cfrac{3}{8} \times 3 \cfrac{5}{8}.
Convert to improper fractions.
Convert the mixed number to an improper fraction.
3 \cfrac{5}{8}=\cfrac{29}{8}
Multiply the numerators together.
\cfrac{3}{8} \times \cfrac{29}{8}=\cfrac{87}{}
Multiply the denominators together.
\cfrac{3}{8} \times \cfrac{29}{8}=\cfrac{87}{64}
If possible, simplify or convert to a mixed number.
The numerator is greater than the denominator, so the improper fraction can be converted to a mixed number.
\cfrac{87}{64}=1 \cfrac{23}{64}
The product cannot be simplified. 23 and 64 only have a common factor of 1.
So, \cfrac{3}{8} \times \cfrac{29}{8}=\cfrac{87}{64} \, or \, 1 \cfrac{23}{64}
1. Solve \cfrac{1}{3} \times \cfrac{9}{10}.
To solve using a model, draw a rectangle. Divide one side into thirds.
Divide the other side into tenths.
Shade in \cfrac{1}{3} with blue and \cfrac{9}{10} with yellow.
The product is where the fractions overlap in green.
The model shows \cfrac{9}{10} of \cfrac{1}{3}, so \cfrac{1}{3} \times \cfrac{9}{10}=\cfrac{9}{30}, because there are 9 green squares and the whole has 30 squares in total.
The product can be simplified.
Both 9 and 30 have a factor of 3, so they can be divided by 3 : \cfrac{9 \; \div \; 3}{30 \; \div \; 3}=\cfrac{3}{10}.
So, \cfrac{1}{3} \times \cfrac{9}{10}=\cfrac{9}{30} \, or \, \cfrac{3}{10}.
2. Solve \cfrac{5}{6} \times \cfrac{4}{5}.
To solve using a model, draw a rectangle. Divide one side into sixths.
Divide the other side into fifths.
Shade in \cfrac{5}{6} with yellow and \cfrac{4}{5} with blue.
The product is where the fractions overlap in green.
The model shows \cfrac{4}{5} of \cfrac{5}{6}, so \cfrac{5}{6} \times \cfrac{4}{5}=\cfrac{20}{30}, because there are 20 green squares and the whole has 30 squares in total.
The product can be simplified.
Both 20 and 30 have a factor of 10, so they can be divided by 10 : \cfrac{20 \; \div \; 10}{30 \; \div \; 10}=\cfrac{2}{3}.
So, \cfrac{5}{6} \times \cfrac{4}{5}=\cfrac{20}{30} \; or \; \cfrac{2}{3}.
3. Solve \cfrac{11}{12} \times \cfrac{3}{10}.
Multiply the numerators together: \cfrac{11}{12} \times \cfrac{3}{10}=\cfrac{33}{}.
Then, multiply the denominators together: \cfrac{11}{12} \times \cfrac{5}{10}=\cfrac{33}{120}.
The product cannot be simplified. 33 and 120 only have a common factor of 1.
S0, \cfrac{11}{12} \times \cfrac{5}{10}=\cfrac{33}{120}.
4. Solve \cfrac{2}{11} \times 5.
Write 5 as an improper fraction, 5=\cfrac{5}{1}.
Then, multiply the numerators together: \cfrac{2}{11} \times \cfrac{5}{1}=\cfrac{10}{}.
Then, multiply the denominators together: \cfrac{2}{11} \times \cfrac{5}{1}=\cfrac{10}{11}.
The product cannot be simplified. 10 and 11 only have a common factor of 1.
So, \cfrac{2}{11} \times \cfrac{5}{1}=\cfrac{10}{11}.
5. Solve 3 \cfrac{2}{3} \times 1 \cfrac{1}{5}. Write the product as a mixed number in lowest terms.
Convert the mixed numbers to improper fractions.
\hspace{1cm} 3 \cfrac{2}{3}=\cfrac{11}{3} \hspace{1cm} and \hspace{1cm} 1 \cfrac{1}{5}=\cfrac{6}{5}
Then, multiply the numerators together: \cfrac{11}{3} \times \cfrac{6}{5}=\cfrac{66}{}.
Then, multiply the denominators together: \cfrac{11}{3} \times \cfrac{6}{5}=\cfrac{66}{15}.
The numerator is greater than the denominator, so the improper fraction can be converted to a mixed number.
\cfrac{66}{15}=4 \cfrac{6}{15}
The product can be simplified.
Both 6 and 15 have a factor of 3, so they can be divided by 3 : \cfrac{6 \; \div \; 3}{15 \; \div \; 3}=\cfrac{2}{5}.
So, \cfrac{11}{3} \times \cfrac{6}{5}=\cfrac{66}{15} \; or \; 4 \cfrac{2}{5}.
6. The dimensions of a rectangular wall are 4 \cfrac{2}{5} \mathrm{m} by 2 \cfrac{1}{4} \mathrm{m}.
One tin of paint can cover an area of 3 square meters. How many tins of paint will you need to paint the entire wall?
The area of a rectangle is \text { base } \times \text { height } therefore to work out the area of the wall we need to calculate 4 \cfrac{2}{5} \times 2 \cfrac{1}{4}.
Convert the mixed numbers to improper fractions.
\hspace{1cm} 4 \cfrac{2}{5}=\cfrac{22}{5} \hspace{1cm} and \hspace{1cm} 2 \cfrac{1}{4}=\cfrac{9}{4}
Then, multiply the numerators together: \cfrac{22}{5} \times \cfrac{9}{4}=\cfrac{198}{}.
Then, multiply the denominators together: \cfrac{22}{5} \times \cfrac{9}{4}=\cfrac{198}{20}.
The numerator is greater than the denominator, so the improper fraction can be converted to a mixed number.
\cfrac{198}{20}=9 \cfrac{18}{20}
The product can be simplified.
Both 2 and 20 have a factor of 2, so they can be divided by 2 : \cfrac{18 \; \div \; 2}{20 \; \div \; 2}=\cfrac{9}{10}.
So, \cfrac{22}{5} \times \cfrac{9}{4}=\cfrac{198}{20} \; or \; 9 \cfrac{9}{10}.
We have 9 \cfrac{9}{10} \mathrm{m}^{2} of wall to paint and each tin can cover 3 m^2.
3 tins can cover 9 m^2\left(3 \times 3 m^2\right), therefore you need to buy 4 tins of paint to cover the entire 9 \cfrac{9}{10} m^2 wall.
No, when you multiply fractions, you multiply the fractions together and do not take the reciprocal of the second fraction. When you divide fractions, you multiply by the reciprocal of the divisor.
It is important to know the following terms…
◌ Denominator: the bottom number
◌ Numerator: the top number
◌ Product: the answer to a multiplication equation
While students are encouraged to use the greatest common factor (GCF) to simplify the products to their lowest terms, it is not a requirement for their understanding of this skill. Additionally, each state has different expectations of when students should use lowest terms. Refer to state standards for clarification.
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