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Graphing linear equations Interpreting graphs Plot points on a graphHere you will learn about how to find the y intercept from a straight line graph, including straight lines in the slope intercept form, y=mx+b and standard form, ax+by=c.
Students will first learn about how to find the y intercept in 8 th grade math with their work with linear functions.
Finding the y intercept of a straight line is an important skill used to solve algebraic and real-life problems involving straight line graphs.
The intercepts of a graph are where the graph crosses the coordinate axes.
You can find the y intercepts of graphs of all types of functions including straight lines, quadratic functions, cubic functions and others. In this case, the y intercept is the point where the function crosses or intercepts the y -axis.
To find the y intercept(s) of a line:
Substitute x=0 into the equation of the function and evaluate for y.
To find the x intercept(s) of a line:
Substitute y=0 into the equation of the function and evaluate for x.
Note, this is a useful strategy to draw the equation of a straight line.
Step-by-step guide: Graphing Linear Equations
Example
The y intercept of a straight line is the value of y when the x -coordinate is zero.
In this real life example, the y intercept represents the starting value or fixed price, with the slope or gradient representing the unit rate or rate of change.
Let’s look at some examples.
A straight line has the equation, in standard form, 4x-3y=18. Find the y intercept of the line.
To find the y intercept, substitute x=0 into the equation.
4(0)-3y=18Now solve the equation to find the corresponding y value.
\begin{aligned}-3y&=18 \\\\ y&=-6 \end{aligned}The y intercept is -6 and has coordinate (0,-6).
Note: If any function is of the form y=f(x)+\text{constant}, the constant is the y intercept. This is because the y -intercept is always when the x -value is 0, so when substituting 0 for x the constant is going to be the y -value.
See examples of different types of polynomials below.
How does this relate to high school math?
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DOWNLOAD FREEIn order to find the y intercept, you need to:
Find the y intercept of the line y=2x-5.
2Solve the equation for \textbf{y}.
This equation gives y=-5.
The y intercept is -5.
It has coordinates (0,-5).
Note: This is the special case where the equation is in the form y = [function of x ] + \; c (constant). In this case c=-5 so the y intercept is (0,-5).
Find the y intercept of the line y=\cfrac{1}{2}x+3
Substitute \textbf{x} = \bf{0} into the equation of the line.
Solve the equation for \textbf{y}.
This equation gives y=3.
The y intercept is 3.
It has coordinates (0,3).
Find the y intercept of the line y=9x-14.
Substitute \textbf{x} = \bf{0} into the equation of the line.
Solve the equation for \textbf{y}.
This equation gives y=-14.
The y intercept is -14.
It has coordinates (0,-14).
Find the y intercept of the line 2x+5y=20.
Substitute \textbf{x} = \bf{0} into the equation of the line.
Solve the equation for \textbf{y}.
The y intercept is 4.
It has coordinates (0,4).
Find the y intercept of the line 3x-4y=24.
Substitute \textbf{x} = \bf{0} into the equation of the line.
Solve the equation for \textbf{y}.
The y intercept is -6.
It has coordinates (0,-6).
Find the y intercept of the line 7x+9y=36.
Substitute \textbf{x} = \bf{0} into the equation of the line.
Solve the equation for \textbf{y}.
The y intercept is 4.
It has coordinates (0,4).
1. State the coordinate of the y intercept of the line y=3x-2.
Substitute x=0 to give
\begin{aligned}y&=3(0)-2 \\\\ y&=-2 \end{aligned}
The coordinate of the y -intercept is (0,-2).
2. Find the coordinate of the y intercept of the line y=3x-6.
Substitute x=0 to give
\begin{aligned}y&=3(0)-6 \\ y&=-6 \end{aligned}
The coordinate of the y -intercept is (0,-6).
3. The equation of a line is given as y=8-3x. Find the y intercept.
When x=0,
\begin{aligned}y&=8-3(0) \\\\ y&=8\end{aligned}
4. The equation of a line is given as x-3y=9. Find the y intercept.
When x=0,
\begin{aligned}-3y&=9 \\\\ y&=-3 \end{aligned}
5. The equation of a line is given as 5x-4y=10. Find the y intercept.
When x=0,
\begin{aligned}5(0)-4y&=10 \\\\ -4y&=10 \\\\ y&=-2.5 \end{aligned}
6. The equation of a line is given as -2x+12y=6. Find the y intercept.
When x=0,
\begin{aligned}-2(0)+12y&=6 \\\\ 12y&=6 \\\\ y&=\cfrac{6}{12}=\cfrac{1}{2} \end{aligned}
The process for finding the x -intercept of a line is similar to finding the y -intercept. Instead of substituting x=0, you would substitute y=0, and solve the equation for x.
Yes, the process for finding the y -intercept in point-slope form is similar to any other linear equation. You will substitute x=0 into the equation and then solve for y.
To find the slope of the line, you will use the formula: m=\cfrac{y_{2}-y_{1}}{x_{2}-x_{1}}, where the slope (m), is found by inserting the x -coordinate and y -coordinate from two points on a given line.
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