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Simplifying expressions Expanding expressions Combining like termsHere you will learn about linear equations, including how to graph linear equations and how to solve linear equations.
Students will first learn about linear equations as part of expression and equations in 8th grade math and will continue to use them throughout high school.
A linear equation is an algebraic equation that contains variables that have an exponent that is not higher than one. A linear equation is called linear because when you plot the graph of the linear function, it will make a straight line graph.
Examples of equations
Nonlinear equations are a type of equations where terms can have variables raised to powers other than one, or terms that are multiplied or divided.
Examples of nonlinear equations:
All linear equations have an equal sign, this means that everything on the left-hand side of the sign is exactly the same as everything on the right-hand side.
The linear equation formula is the way of expressing a linear equation and can be done in various ways, depending on the number of variables present.
The standard form is ax+by=c, where a, b and c are constants.
For example,
\begin{aligned}& 2x-3y+4=0 \\\\ &3y-7x=8 \\\\ &4x=12 \end{aligned}
Slope-intercept form
The slope-intercept form of a linear equation can be written as y=mx+b, where m is the slope of a line and b is the y -intercept.
Point slope form
The point slope form of a linear equation can be written as y-y_1=m\left(x-x_1\right), where m is the slope of the line and \left(x_1, y_1\right) is a point on the line.
Linear equations are related to coordinate grids, as they provide a way to graphically represent and solve linear equations.
For example,
Given the equation
\begin{aligned}&2x-3y+4=0 \\\\ &3y-7x=8 \\\\ &4x=12\end{aligned}
we can graphically represent this equation on a coordinate grid
A one variable linear equation with the variable x forms a vertical line that is parallel to the y -axis.
For example,
Given the equation x-4=0
You need to isolate the variable by adding 4 to both sides of the equation.
\begin{aligned}& x-4=0 \\\\ & +4+4 \\\\ & x=4\end{aligned}
To graph the line x=4, you will draw a straight, vertical line through point (4,0).
The slope in a vertical line is undefined.
A one variable linear equation with the variable y forms a horizontal line that is parallel to the y -axis.
For example,
Given the equation y+6=0
You need to isolate the variable by subtracting 6 from both sides of the equation.
\begin{gathered}y+6=0 \\\\ -6-6 \\\\ y=-6\end{gathered}
To graph the line y=-6, you will draw a straight, vertical line through point (0,-6).
The slope in a horizontal line is 0.
How does this relate to 8 th grade math?
Use this worksheet to check your 7th grade to high school students’ understanding of linear equations. 15 questions with answers to identify areas of strength and support!
DOWNLOAD FREEUse this worksheet to check your 7th grade to high school students’ understanding of linear equations. 15 questions with answers to identify areas of strength and support!
DOWNLOAD FREEIn order to solve a linear equation, you will need to:
Solve 3 x+6=18.
Both sides of the equation are simplified.
2Isolate the variable on one side of the equation.
Here, the opposite of +6 is -6.
3Solve for the variable.
Here,
3 x=3\times x, so divide by 3.
x=4
Solve 5 x+6=2 x+9.
Simplify both sides of the equation.
Here, 2x is smaller than 5x, so eliminate it by -2x.
Isolate the variable on one side of the equation.
Solve for the variable.
Here,
3x=3\times x, so we divide by 3.
Solve -3 x-11=-12 x+16.
Simplify both sides of the equation.
Here -3x is smaller than -12x, so eliminate it by adding 3x to both sides.
\begin{aligned} -3 x-11&=-12 x+16 \\\\ +3 x \hspace{0.2cm} & \hspace{0.5cm}+3 x \\\\ -11&=-9 x+16\end{aligned}
Isolate the variable on one side of the equation.
To isolate the variable, subtract 16 from both sides of the equal sign.
\begin{aligned} -11&=-9 x+16 \\\\ -16 & \hspace{0.5cm}-16 \\\\ -27&=-9 x\end{aligned}
Solve for the variable.
To solve for the variable, divide each side by -9.
\begin{aligned} -27&=-9 x \\\\ \div(-9) & \hspace{0.2cm} \div(-9) \\\\ x&=3\end{aligned}
Solve 4(x-2)=12.
Simplify both sides of the equation.
Start by distributing the 4 to the factors within the parentheses.
Isolate the variable on one side of the equation.
Here the opposite of -8 is +8, so you will add 8 to both sides.
\begin{aligned}4 x-8&=12 \\\\ +8 & \hspace{0.3cm} +8 \\\\ 4 x&=20\end{aligned}
Solve for the variable.
Because 4x=4\times x, divide by 4 to solve for the variable.
Solve -2(4 x+10)=12.
Simplify both sides of the equation.
Start by distributing the -2 to the factors within the parentheses.
\begin{aligned}& -2(4 x+10)=12 \\\\ & -8 x-20=12\end{aligned}
Isolate the variable on one side of the equation.
The opposite of -20 is +20, so you will add 20 to both sides.
\begin{aligned}-8 x-20&=12 \\\\ +20 & \hspace{0.2cm} +20 \\\\ -8 x&=32\end{aligned}
Solve for the variable.
To solve for the variable, we will divide both sides of the equation by -8.
\begin{aligned}-8 x& =32 \\\\ \div(-8) & \hspace{0.2cm} \div(-8) \\\\ x&=4\end{aligned}
Solve \cfrac{5 x-2}{4}=\cfrac{2 x+2}{2} \, .
Simplify both sides of the equation.
Cross multiply, by multiplying each fraction by the denominator on the other side of the equal sign to get rid of the fractions.
\begin{aligned}& (5 x-2) \times(2)=(2 x+2) \times(4) \\\\ & 10 x-4=8 x+8\end{aligned}
Isolate the variable on one side of the equation.
Start by subtracting 8x from both sides of the equation.
\begin{aligned} 10 x-4&=8 x+8 \\\\ - \, 8 x \hspace{0.1cm} & \hspace{0.2cm}-8 x \\\\ 2 x-4&=8\end{aligned}
Then add 4 to both sides of the equation.
\begin{aligned}2 x-4&=8 \\\\ +4 \hspace{0.1cm} & \hspace{0.2cm} +4 \\\\ 2 x&=12\end{aligned}
Solve for the variable.
Solve for x by dividing both sides of the equation by 2.
\begin{aligned} 2 x & =12 \\\\ \div 2 & \hspace{0.2cm} \div 2 \\\\ x&=6\end{aligned}
1. Solve:
2 x+8=20
2 x+8=20
First, subtract 8 from both sides.
2 x=12
Solve for the variable by dividing both sides by 2.
x=6
2. Solve:
5 x-3=12
5 x-3=12
First, add 3 to both sides.
5 x=15
Then divide both sides by 5.
x=3
3. Solve:
2 x-7=x+5
2 x-7=x+5
First, subtract x from both sides.
x-7=5
Then add 7 to both sides to solve for the variable.
x=12
4. Solve:
7 x-3=4 x+15
7 x-3=4 x+15
Start by subtracting 4x from both sides.
3 x-3=15
Then add 3 to both sides.
3 x=18
To solve for the variable, divide both sides by 3.
x=6
5. Solve:
5(x-3)=10
5(x-3)=10
Start by dividing both sides by 5.
x-3=2
Add 3 to both sides of the equal sign to solve for x.
x=5
6. Solve:
3(x-3)=6(x+5)
3(x-3)=6(x+5)
Start by distributing within the parenthesis.
3 x-9=6 x+30
Then, subtract 3x from both sides.
-9=3 x+30
Subtract 30 from both sides.
-39=3 x
To solve for the variable, divide both sides by 3.
x=-13
7. Solve:
\cfrac{3x+1}{2}+\cfrac{2x-2}{4}
\cfrac{3x+1}{2}+\cfrac{2x-2}{4}
Cross multiply, by multiplying each fraction by the denominator on the other side of the equal sign to get rid of the fractions.
(3 x+1) \times 2=(2 x-2) \times 4
12x+4=4x-4
From both sides of the equation, subtract 4x .
8x+4=-4
and subtract -4
8x=-8
Finally divide by 8.
x=-1
Yes, a linear equation in two variables can have an infinite amount of solutions. The solutions are all of the points that lie on the line represented by the given equation.
Simultaneous linear equations are a system of linear equations, two or more, with two or more variables. Solving such systems involves finding values for the variables that satisfy all the equations simultaneously.
See also: Systems of linear equations
Quadratic equations are an extension of linear equations, representing a more complex relationship between variables. Linear equations create straight lines, while quadratic equations create a parabola, or a U -shaped curve.
The general form of linear equations is another way to say “standard form”. The standard form, or general form, is ax+by=c, where a, b and c are constants.
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